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	<title>Banach lattice Archives - RGOSA</title>
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		<title>Is every norm-dense order dense sublattice super order dense?</title>
		<link>https://rgosa.net/forums/topic/is-every-norm-dense-order-dense-sublattice-super-order-dense-2/</link>
		
		<dc:creator><![CDATA[Eugene Bilokopytov]]></dc:creator>
		<pubDate>Wed, 09 Apr 2025 08:44:03 +0000</pubDate>
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					<description><![CDATA[Let $F$ be a norm-dense linear sublattice of a Banach lattice $E$, which is order dense, i.e. for every $e\texttt{ > } 0$ there is $f\in F$ such that $0 \lt f\le e$. Note that since $E$ is Archimedean, order denseness implies that for every $e\ge 0$ there is $A\subset F$ such that $e=\bigvee A$.&#8230;&#160;<a href="https://rgosa.net/forums/topic/is-every-norm-dense-order-dense-sublattice-super-order-dense-2/" rel="bookmark"><span class="screen-reader-text">Is every norm-dense order dense sublattice super order dense?</span></a>]]></description>
		
		
		
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